43. A force F = ai +3j +6k is acting at a point
r= 2i -6j - 12k Find the value of a for which
angular momentum about origin is conserved.
(1) o
(2) 1
(3) -1
(4) 2
Answers
Answered by
60
Answer:
(c)-1
Explanation:
refer to attachment
Attachments:
Answered by
3
Answer:
-1
Explanation:
F=ai+3j+6k(think 'a' as alpha)
r=2i-6j-12k
T=F.r
=i j k
a 3 6
2 -6 -2
=(-36+36)i - (12+12)j - (6+6)k
-(36+36)i get cancelled
=12+12a=0. 6+6a=0
=-1. -1
Hope it helps u
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