Question

46. A bullet is projected upwards from the top of
a tower of height 90 m with the velocity 30
ms- making an angle 30° with the horizontal.
The time taken by it to reach the ground is
=10 ms)​

Answer 1

Answer:

h=90m.

u=50m/sec.

vertical component of initial velocity

uy=50sin30°=30*1/2=15m/s.

By the equations of motion

h=uy t+at^2/2

90=15 t+ 10 t^2/2

90=15 t+5 t^2

18=t^2 +3 t

t^2 +3t -18=0

by solving it we will get

t=-6 or 3

time cannot be negative.

t=3 seconds.

Time taken by the body is 3 seconds

Hope it helps.

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