Question

47x and 3y2 are two three digit numbers. if their product is 162792. find the values of x and y

Answer 1

Answer:

Given,

 47x * 3y2 = 162792

(470 + x)*(300 + 10y + 2) = 162792

141000 + 4700y + 94 + 300x + 10xy + 2x  = 162792

 4700y + 300x + 10xy = 21698

may be you can find your answer further,

even i am stuck here

Answer 2

Step-by-step explanation:

Given,

$47 x * 3 y 2=162792$

$(470+x)^{*}(300+10 y+2)=162792$

$141000+4700 y+94+300 x+10 x y+2 x=162792$

$4700 y+300 x+10 x y=21698$

may be you can find your answer further,

even i am stuck here

47x and 3y2 are two three digits number. if their product is 1,62,792 find the unknown digits x and y

https://brainly.in/question/44357514

#SPJ2