Question

(4a+7b)²-112ab=(4a-7b)²​

Answer 1

Answer:

L.H.S

(4a+7b)²-112ab

=( (4a)²+2×4a×7b+(7b)² ) -112ab

=(16a²+56ab+49b² ) -112ab

=16a²+(56ab-112ab)+49b²

=16a²-56ab+49b²

=(4a)²-2×4a×7b+(7b)²

=(4a-7b)²

R.H.S

=(4a-7b)²

i.e L.H.S = R.H.S

hence proved