Question

4m+3n= 12 pls solve it

Answer 1

HERE'S YOUR ANSWER....✌️✌️

4m + 3n - 12 = 0

Solving ,
4m + 3n = 12

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-3n' to each side of the equation.

4m + 3n + -3n = 12 + -3n

Combine like terms:
3n + -3n = 0

4m + 0 = 12 + -3n

4m = 12 + -3n

Divide each side by '4'.

m = 3 + -0.75n

Divide each side by '3'

n = 4 + -1.33m

Answer 2

Answer:

Required solution is $m = \frac{12 - 3n}{4} \: and \: n = \frac{12 - 4m}{3}$

Step-by-step explanation:

Given,

$4m + 3n = 12.....(1)$

From equation (1),

$4m + 3n = 12 \\ 4m = 12 - 3n \\ m = \frac{12 - 3n}{4} ....(2)$

Therefore,for all values of n, value of m is $\frac{12 - 3n}{4}$

For example,

If $n = 4$ then

$m = \frac{12 - 3 \times 4}{4} \\ = \frac{12 - 12}{4} \\ = \frac{0}{3} \\ = 0$

Again from from equation (1),

$4m + 3n = 12 \\ 3n = 12 - 4m \\ n = \frac{12 - 4m}{3}$

Therefore for all values of m, value of n is $\frac{12 - 4m}{3}$

For example,

If $m = 3$ then

$n = \frac{12 - 4 \times 3}{3} \\ = \frac{12 - 12}{3} \\ = \frac{0}{3} \\ = 0$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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