Question

4n² + 5n - 636 = 0 Pls Factorise It...........

Answer 1

You want that I should factorize this: $4n^{2} + 5n - 636$
Let $a = 4, b = 5, c = -636$. $a$ is the coefficient of $n^{2}$, $b$ is the coefficient of $n$, and $c$ is the constant. 
Find out two numbers that multiply to give $ac$ and add to give $b$. 
Here, $ac = 4 * (-636) = -2544$ and $b = 5$. 
So, in other words, we have to find two numbers that multiply to give -2544 and add to give 5 (or +5). 
Find out the factors of 2544. 
1 × 2544
2 × 1272
3 × 848
4 × 636
6 × 424
8 × 318
12 × 212
16 × 159
24 × 106
48 × 53
Now, check. It seems that if we add -48 and 53, we get five. 
(-48) × 53 = -2544 (= ac)
-48 + 53 = 5 (=b)
∴ The two numbers are -48 and 53. 

Now, in the given polynomial, suppose that 5n is the midde term. Break the middle term into two parts, such that their coefficients should be -48 and 53 and their variable should be the same, i.e., n. 

Now, see these steps to understand. 
$4n^{2} + 5n - 636$
$= 4n^{2} -48n + 53n - 636$
$= 4n(n-12) + 53(n-12)$
$= (4n+53)(n-12)$
FACTORIZATION DONE !!!

If you are not able to understand anything, ask me in the comments. 

Hope this may help you. 

Answer 2

Answer:

Step-by-step explanation:

4n^2+5n-636=0

4n^2-48n+53n-636=0

4n(n-12)+53(n-12)=0

(4n+53)(n-12)=0

n=12andn=-53/4