4sinα+3cosα=5 then tanα=?
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By dividing cosa in the expression
4sina/cosa+3cosa/cost = 5
4sina/cosa+3*1 = 5
4tana+3 = 5
4tana = 2
Tan a = 1/2
(sin/cos = tan)
4sina/cosa+3cosa/cost = 5
4sina/cosa+3*1 = 5
4tana+3 = 5
4tana = 2
Tan a = 1/2
(sin/cos = tan)
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