Question

find the positive root of 3xsqrare +6=9

Answer 1

u can find this by
3x^2+6=9
3x^+6-9 = 0
3(x^2 +2- 3 ) = 0
x^2 -1 =0
x^2 = 1
x = root 1
x= 1
(1) is the positive root for this equation

Answer 2

We have , 3 x 2 + 6 = 9 ⇒ 3 x 2 = 9 - 6 ⇒ 3 x 2 = 3 ⇒ x 2 = 3 ⇒ x = ± 3 = ± 31/4 now, positive root is 3 1 / 4 .