Question

4sin theta cos theta = 1 - 2sin theta + 2 cos theta​

Answer 1

Answer:

Though it is not a complete answer

But still for now try this as it answer

Step-by-step explanation:

Hope it would help u

Answer 2

Answer:

4sinαcosα = 1+2cosα-2sinα

1+2cosα-2sinα-4sinαcosα = 0

Now, factorizing them, we get,

(1+2cosα) - 2sinα(1+2cosα) = 0

(1-2sinα)(1+2cosα) = 0

1-2sinα = 0 or 1+2cosα = 0

Sinα = ½ or cosα = -1/2

Sinα = Sinπ/6 or cosα = cos2π/3

So, α = nπ+(-1)^nπ/6 or α = 2nπ+- 2π/3

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