4x^2 - √3x - 5=0 explain this question in completing the method of square ,give me total expl....n of this problem
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Hi ,
4x² - √3x - 5 = 0
divide each term with 4 , we get
x² - √3/4 x - 5/4 = 0
x² - 2 × x × ( √3/8 ) + ( √3/8 )² = 5/4 - ( √3/8 )²
( x - √3/8 )² = 5/4 - 3/64
= ( 80 - 3 ) /64
= 77/64
( x - √3/8 ) = ± √( 77/64)
x = √3/8± √77/8
x = ( √3 ± √77 ) /8
I hope this helps you.
:)
4x² - √3x - 5 = 0
divide each term with 4 , we get
x² - √3/4 x - 5/4 = 0
x² - 2 × x × ( √3/8 ) + ( √3/8 )² = 5/4 - ( √3/8 )²
( x - √3/8 )² = 5/4 - 3/64
= ( 80 - 3 ) /64
= 77/64
( x - √3/8 ) = ± √( 77/64)
x = √3/8± √77/8
x = ( √3 ± √77 ) /8
I hope this helps you.
:)
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