Question

4x^2+y^2+z^2-4xy-2yz-4zx

Answer 1

Best Answer

4x^2 + y^2 + z^2 - 4xy - 2yz +4xz

= (- 2x)^2 + y^2 + (-z)^2 + 2(-2x)(y) + 2y(-z) + 2(-2x)(-z)

= (-2x + y - z)^2

Answer 2

Hello, 

It can be solve by the identity
(a + b)² = a² + 2ab + b² 

So: 
4x² + y² + z² - 4xy - 2yz + 4xz 

 = (2x)² + (-y)² + z² + 2(2x)(-y) + 2(-y)z + 2(2x)z

 = (2x - y + z)² 

I hope helps you