Math, asked by anilpatil28413, 8 months ago

4x+3y-4=0;6x=8-5y.. solve the following simultaneous equations using Cramer rule​

Answers

Answered by ruwanyaart
8

Answer:

X=-2

Y=4

Step-by-step explanation:

4X+3Y-4=0

4X+3Y=4

3Y=4-4X

Y=(4-4X)/3

THEN

6X=8-5Y

6X=8-5(4-4X)/3

6X=8-20(1-X)/3

18X=24-20(1-X)

18X=24-20+20X

18X-20X=4

-2X=4

X=-2

SO THAT,

Y=(4-4*-2)/3

Y=12/3=4

Answered by darshankedare02
2

Hii

you are so cute

4x + 3y – 4 = 0; 6x = 8 – 5y

(ii) 4x + 3y – 4 = 0; 6x = 8 – 5y

Sol. 4x + 3y – 4 = 0

∴ 4x + 3y = 4

6x = 8 – 5y

∴ 6x + 5y = 8

D

=

4

3

=

(4 × 5) – (6 × 3)

=

20 – 18

=

2

6

5

DX

=

4

3

=

(4 × 5) – (8 × 3)

=

20 - 24

=

- 4

8

5

DY

=

4

4

=

(4 × 8) – (6 × 4)

=

32 - 24

=

8

6

8

By Cramer's rule,

x

=

Dx

=

-4

=

-2

D

2

y

=

Dx

=

8

=

4

D

2

x = - 2 and y = 4 is the solution of given simultaneous equations.

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