Question

solve by cross multiplication 3x+y=13 and x-3y+9=0​

Answer 1

Answer:

hope it will be useful to you my friend

Step-by-step explanation:

if it is wrong means I will correct it

Answer 2

The correct answer is x is -6 and that of y is  $\frac{-7}{4}$.

Given: 3x+y=13 and x-3y+9=0​.

To Find: Solve by cross multiplication.

Solution:

Firstly, shift every term in left hand side.

$\frac{x}{b1c2-c1b2} =\frac{y}{c1a2-a1c2}=\frac{1}{a1b2-b2a1}$

$\frac{x}{9*1-(-3)*(-13)} =\frac{y}{(-13)*1+9*3}=\frac{1}{3(-3)+1}$

$\frac{x}{9+39} =\frac{y}{-13+27}=\frac{1}{-9+1}$

$\frac{x}{48} =\frac{y}{14}=\frac{1}{-8}$

Taking I and III

$\frac{x}{48}=\frac{1}{-8}$

x = - 6

Taking II and III

$\frac{y}{14}=\frac{1}{-8}$

y = $\frac{-7}{4}$

Hence, the value of x is -6 and that of y is  $\frac{-7}{4}$.

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