4x +6/y =15 and 6x - 8/y = 14
Answers
Answered by
10
Hey!!!!
We have
=> 4x + 6/y = 15
and
=> 6x - 8/y = 14
Let 1/y = a
Thus equations become
=> (4x + 6a = 15)3
and
=> (6x - 8a = 14)2
Now the equations become
=> 12x + 18a = 45
and
=> 12x - 16a = 28
Subtract the second from first
=> 12x + 18a - (12x - 16a) = 45 - 28
=> 34a = 17
=> a = 1/2
Thus
=> y = 2
Using y in any equation
=> 4x + 6/2 = 15
=> 4x = 12
=> x = 3
Hope this helps ✌️
We have
=> 4x + 6/y = 15
and
=> 6x - 8/y = 14
Let 1/y = a
Thus equations become
=> (4x + 6a = 15)3
and
=> (6x - 8a = 14)2
Now the equations become
=> 12x + 18a = 45
and
=> 12x - 16a = 28
Subtract the second from first
=> 12x + 18a - (12x - 16a) = 45 - 28
=> 34a = 17
=> a = 1/2
Thus
=> y = 2
Using y in any equation
=> 4x + 6/2 = 15
=> 4x = 12
=> x = 3
Hope this helps ✌️
problem999:
hey bro by substitution also
Answered by
5
heyy dear !!
..solution:
▶to find x and y
◼By method of elimination:
4x+6/y=15.....1)
6x-8/y=14...... 2)
on multiplying eq .1) by 6 and eq.2) by 4 we have:
24x+36/y=90
24x-32/y=56
on solving both we have :
36/y+32/y=34
(36+32)/y=34
34y=68
y=2
on putting value of y in eq.1) we have:
4x=12
x=3
x=3,y=2
hope it helps✌✴
..solution:
▶to find x and y
◼By method of elimination:
4x+6/y=15.....1)
6x-8/y=14...... 2)
on multiplying eq .1) by 6 and eq.2) by 4 we have:
24x+36/y=90
24x-32/y=56
on solving both we have :
36/y+32/y=34
(36+32)/y=34
34y=68
y=2
on putting value of y in eq.1) we have:
4x=12
x=3
x=3,y=2
hope it helps✌✴
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