Question

4x + 7 /9-3x=1/4 solve for the value of x​

Answer 1

Answer:

-1

Step-by-step explanation:(4x+7)=9-3x

16x+28=9-3x

19x = -19

x = -1

Answer 2

Answer:

$\dfrac{4x+7}{9-3x}=\dfrac{1}{4}\quad :\quad x=-1$

Step-by-step explanation:

$\dfrac{4x+7}{9-3x}=\dfrac{1}{4}$

$\gray{\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\dfrac{a}{b}=\dfrac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c}$

$\left(4x+7\right)\cdot \:4=\left(9-3x\right)\cdot \:1$

$\gray{\mathrm{Simplify\:}\left(9-3x\right)\cdot \:1:\quad 9-3x}$

$\left(4x+7\right)\cdot \:4=9-3x$

$\gray{\mathrm{Expand\:}\left(4x+7\right)\cdot \:4:\quad 16x+28}$

$16x+28=9-3x$

$\gray{\mathrm{Subtract\:}28\mathrm{\:from\:both\:sides}}$

$16x+28-28=9-3x-28$

$\gray{\mathrm{Simplify}}$

$16x=-3x-19$

$\gray{\mathrm{Add\:}3x\mathrm{\:to\:both\:sides}}$

$16x+3x=-3x-19+3x$

$\gray{\mathrm{Simplify}}$

$19x=-19$

$\gray{\mathrm{Divide\:both\:sides\:by\:}19}$

$\dfrac{19x}{19}=\dfrac{-19}{19}$

$\gray{\mathrm{Simplify}}$

$x=-1$