Question

4x²+x-5=0 find using formula​

Answer 1

Answer:

$\tt \: 4 {x }^{2} + x - 5 = 0 \\ \longrightarrow \tt \: {4x}^{2} - 4x + 5x - 5 = 0 \\\longrightarrow \tt \: 4x(x - 1) + 5(x - 1) \\\longrightarrow \tt \: (x - 1)(4x + 5)$

Answer 2

Answer:

4x²+x-5=0

⇒4x² - 4x + 5x - 5 = 0

⇒4x (x - 1) + 5 (x - 1)

⇒(x - 1) (4x + 5)

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