Question

The cost of a machine depreciates by 10% every year.
If its present worth is *18,000; what will be its value
after 3 years?
by 200% every​

Answer 1

Step-by-step explanation:

P= rs. 18000

R= 10%

n= 3 years

So, the price of the machine after 3 years

= 18000×(1-10/100)³

=18000×{(10-1)/10}³

=18000×(9/10)×(9/10)×(9/10)

= 18×729

=Rs. 13122

Answer 2

in this type of questions you can apply CI formula bcoz they increase or decrease in same manner as in CI our intrest increase .

I hope you got it.