Chemistry, asked by harry2261, 1 year ago

The ratio of radii of first orbital of h,he+ and li2+ is

Answers

Answered by kobenhavn
9

Thus the ratio of radii of first orbital of H ,He^+ and Li^{2+}  is 3: 2: 1

Explanation:

Radius of an atom is given by the Bohr's equation:

r=\frac{0.529\times n^2}{Z}A^0

where,

r = radius of atom

n = number of orbit, for first n = 1, for second n = 2 and so on.

Z = Atomic number

a) For first orbital of H

r=\frac{0.529\times 1^2}{1}A^0

r=0.529A^0

b) For first orbital of He^+

r=\frac{0.529\times 1^2}{2}A^0

r=0.264A^0

b) For first orbital of Li^{2+}

r=\frac{0.529\times 1^2}{3}A^0

r=0.176A^0

Thus the ratio of radii of first orbital of H ,He^+ and Li^{2+}  is 3: 2: 1

Learn more about Bohr radius

brainly.in/question/3266241

brainly.in/question/276068

Answered by jiyapadhariya
3

Answer:

Thus the ratio of radii of first orbital of H ,He^+He

+

and Li^{2+}Li

2+

is 3: 2: 1

Explanation:

Radius of an atom is given by the Bohr's equation:

r=\frac{0.529\times n^2}{Z}A^0r=

Z

0.529×n

2

A

0

where,

r = radius of atom

n = number of orbit, for first n = 1, for second n = 2 and so on.

Z = Atomic number

a) For first orbital of H

r=\frac{0.529\times 1^2}{1}A^0r=

1

0.529×1

2

A

0

r=0.529A^0r=0.529A

0

b) For first orbital of He^+He

+

r=\frac{0.529\times 1^2}{2}A^0r=

2

0.529×1

2

A

0

r=0.264A^0r=0.264A

0

b) For first orbital of Li^{2+}Li

2+

r=\frac{0.529\times 1^2}{3}A^0r=

3

0.529×1

2

A

0

r=0.176A^0r=0.176A

0

Thus the ratio of radii of first orbital of H ,He^+He

+

and Li^{2+}Li

2+

is 3: 2: 1

Learn more about Bohr radius

brainly.in/question/3266241

brainly.in/question/276068

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