Math, asked by nqaadri, 1 year ago

4z^2-[3z^2{3^2/2-(a^2+z^2/3)}]​

Answers

Answered by bangtangranger
1

Answer:

3a²z² + z⁴ + -19/2z²

Step-by-step explanation:

4z² - (3z²(3²/2 -(a²+z²/3)))

Distribute:

= 4z² + 3a²z² + z⁴ + -27/2z²

Combine like terms:

= 4z²+ 3a²z² + z⁴ + -27/2z²

= (3a²z²) + (z⁴) + (4z² + -27/2z²)

= 3a²z² + z⁴ + -19/2z²

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