5-2root 3 is irrational number
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Yeah, 5 - 2 √3 is an irrational number.
Proof: Let 5 - 2 √3 is a rational number equal to a .
( 5 - 2 √3 ) = a
Squaring both sides,
( 5 - 2√3 ) ^ 2 = a ^ 2
5 ^ 2 + ( 2 √3 ) ^2 - 2 * 5 * ( 2√3) = a ^ 2
25 + 12 - 20 √3 = a ^ 2
37 - 20√3 = a ^ 2
20√3 = 37 - a ^ 2
√3 = ( 37 - a ^ 2 ) / 20.
Since, a is a rational number so ( 37 - a ^ 2 ) / 20 is also a rational number and it is equal to √3,but a rational number can't be equal to an irrational number.So it contradicts our assumption that 5 - 2 √3 is a rational number.Hence, it is an irrational number.
Proof: Let 5 - 2 √3 is a rational number equal to a .
( 5 - 2 √3 ) = a
Squaring both sides,
( 5 - 2√3 ) ^ 2 = a ^ 2
5 ^ 2 + ( 2 √3 ) ^2 - 2 * 5 * ( 2√3) = a ^ 2
25 + 12 - 20 √3 = a ^ 2
37 - 20√3 = a ^ 2
20√3 = 37 - a ^ 2
√3 = ( 37 - a ^ 2 ) / 20.
Since, a is a rational number so ( 37 - a ^ 2 ) / 20 is also a rational number and it is equal to √3,but a rational number can't be equal to an irrational number.So it contradicts our assumption that 5 - 2 √3 is a rational number.Hence, it is an irrational number.
Aaakkk:
thanks u a lot
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