Question

(5+3√2) prove tha in irrationl namber

Answer 1

It's so simple yaar

Put this (5+3root2)=a/b

Then take all the number and algebra to right side accept root2

Root2=a/b - 5 /3
=a-5b/3b

And u have prooved root 2 irrational so that relation we formed =root 2 and root 2 is irrational
So they are also irrational
Then u can reverse it after proving it irrational if required
............. As this the whole digit is proved irrational.... Hence proved.

pls mark as brainliest.

Answer 2

Hey....

At first we know that √2 is an irrational no.

Now , let (5+3√2 ) be a rational no.

So.. (5+3√2-5)=3√2-------(1)

{rational -rational=rational}

A/Q to eq. (1) 3√2 is a rational no..

Now, 3√2×1/3=√2---------(2)

{rational × rational = rational}

A/Q to eq. (2) √2 is a rational no.. bt we know that √2 is an irrational no so.. our contradict was wrong and...

(5+√2) is an irrational no....

Hope this will help u ...✌✌✌✌✌...