Question

5)

|3 5|

|2
| = 2 ∴ =​

Answer 1

Given: 1+sin2 θ = 3 sin θ cos θ

Dividing L.H.S and R.H.S equations with sin2 θ,

We get, cosec2 θ + 1 = 3 cot θ Since, cosec2 θ – cot2 θ = 1 ⇒

cosec2 θ = cot2 θ +1 ⇒ cot2 θ +1+1 = 3 cot θ ⇒ cot2 θ +2 = 3 cot θ ⇒ cot2 θ –3 cot θ +2 = 0

Splitting the middle term and then solving the equation, ⇒ cot2 θ – cot θ –2 cot θ +2 = 0 ⇒ cot θ(cot θ -1)–2(cot θ +1) = 0 ⇒ (cot θ – 1)(cot θ – 2) = 0 ⇒ cot θ = 1, 2

Since, tan θ = 1/cot θ tan θ = 1, ½ Hence, proved.Read more on Sarthaks.com - https://www.sarthaks.com/884852/if-1-sin-2-3sin-cos-then-prove-that-tan-1-or

Answer 2

Answer:

Answer is 4

Hope it will help you