Math, asked by aloksingh036, 11 months ago

5 - (3a² - 2a) (6 - 3a^2 + 2a)​

Answers

Answered by Anonymous
6

= 5 – (18a²– 9a^4+ 6a³ – 12a + 6a³ – 4a²)

= 5 – (– 9a^4 + 6a³ + 6a³+ 18a²– 4a²– 12a)

= 5 – (– 9a^4 + 12a³ + 14a² – 12a)

= 9a^4 - 12a³ - 14a² + 12a + 5

= (a+1)(3a+1)(a−1)(3a−5)

Similar questions