Question

5. 5x²-4 – 8x find zeroes of polynomial
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Answer 1

Answer:

▶Here's your answer

$5 {x}^{2} - 8x - 4 = 0 \\ \\ 5 {x}^{2} - 10x + 2x - 4 = 0 \\ \\ 5x(x - 2) + 2(x - 2) = 0 \\ \\ (x - 2)(5x + 2) = 0$

⏩So zeroes are 2 and -2/5

Hope it helps ❗

Answer 2

Zeroes are 2 and -2/5.

Hope it helps you!