5х- 6y + 30 = 0 5х + 4y - 20 = 0
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5x-6y+30=0 5x+4y-20=0
5x-6y=-30 (i) 5x+4y=20 (ii)
substract (i) and (ii)
5x + 4y= 20
(-)5x-(+)6y=-(+)30
_____________
10y= 50
------------------------
y= 50/10
y= 5
substitute y in (ii)
5x+4y=20
5x+4(5)=20
5x+20=20
5x=20-20
5x=0
x=-5
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