(5/7×3/4)+(5/7×-1/6) answer in distributive property
Answers
Answer:
(i) -2/3 x 3/5 + 5/2 - 3/5 x 1/6
= -2/3 x 3/5 - 3/5 x 1/6 + 5/2 [by commutativity]
= (-2/3 x 3/5) - (3/5 x 1/6) + 5/2
= 3/5 [-2/3 - 1/6] + 5/2 [by distributivity]
= -3/5 [2/3 + 1/6] + 5/2
= -3/5 [(4 + 1)/6] + 5/2
= -3/5 x 5/6 + 5/2
= -3/6 + 5/2
= -1/2 + 5/2
= (-1 + 5)/2
= 4/2
= 2
(ii) 2/5 x (-3/7) - 1/6 x 3/2 + 1/14 x 2/5
= 2/5 x (-3/7) + 1/14 x 2/5 - 1/6 x 3/2 [by commutativity]
= [2/5 x (-3/7)] + [1/14 x 2/5] - 1/6 x 3/2
= 2/5 [-3/7 + 1/14] - 3/12 [by distributivity]
= 2/5 [(-6 + 1)/14] - 1/4
= 2/5 x (-5/14) - 1/4
= -2/14 - 1/4
= (-4 - 7)/28
= -11/28
Step-by-step explanation:
(i) -2/3 x 3/5 + 5/2 - 3/5 x 1/6
= -2/3 x 3/5 - 3/5 x 1/6 + 5/2 [by commutativity]
= (-2/3 x 3/5) - (3/5 x 1/6) + 5/2
= 3/5 [-2/3 - 1/6] + 5/2 [by distributivity]
= -3/5 [2/3 + 1/6] + 5/2
= -3/5 [(4 + 1)/6] + 5/2
= -3/5 x 5/6 + 5/2
= -3/6 + 5/2
= -1/2 + 5/2
= (-1 + 5)/2
= 4/2
= 2
(ii) 2/5 x (-3/7) - 1/6 x 3/2 + 1/14 x 2/5
= 2/5 x (-3/7) + 1/14 x 2/5 - 1/6 x 3/2 [by commutativity]
= [2/5 x (-3/7)] + [1/14 x 2/5] - 1/6 x 3/2
= 2/5 [-3/7 + 1/14] - 3/12 [by distributivity]
= 2/5 [(-6 + 1)/14] - 1/4
= 2/5 x (-5/14) - 1/4
= -2/14 - 1/4
= (-4 - 7)/28
= -11/28
Answer:
(axb)+(axc)=a(b+c)
a=5/7, b=3/4, c=-1/6
5/7{3/4+(-1/6)}
5/7{3/4-1/6}
LCM of 4,6=24
3/4x6=18/24
1/6x4=4/24
5/7{18/24-4/24}
5/7{(18-4)/24)}
5/7{14/24}
5/7{7/12}
5/7x7/12
=5/12
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