Question

5/7 of a no. exceeded 65 gives 80 find no.

Answer 1

Let the no. be x

ATQ

5x/7+65=80

5x+455=80×7

5x=560-455

5x=105

x=105/5

x=21

Answer 2

Let the number be x,

5x/7 + 65 = 80

5x/7 = 80-65

5x/7 = 15

x/7 = 3

x = 7×3

x = 21


21 is the required number



I hope this will help you

-by ABHAY