Question

5. A hemisperical cont is made up of an
iron sheet 1 cm thick If the radius is im , then find the volume
of the iron used to make the tank​

Answer 1

Answer:

63487.8cm^3

Step-by-step explanation:

.

$r1 = 101 \\ r2 = 100 \\ vol.of \: hemisphere = \frac{2}{3} \pi {r}^{3} \\ = \frac{2}{3} \pi ({r1}^{3} - {r2}^{3} ) \\ = \frac{2}{3} \times \frac{22}{7} ( {101}^{3} - {100}^{3} ) \\ = \frac{2}{3} \times \frac{22}{7} (1030301 - 1000000) \\ = \frac{2}{3} \times \frac{22}{7} \times 30301 \\ = \frac{44 \times 30301}{7 \times 3} \\ = 63487.8 {cm}^{3}$