Question

5. A student recorded the mass of dry raisins as 2.0g and the mass of raisins after soaking as 3.5g. Calculate the percentage of water absorbed by raisins.

Answer 1

just a percent questions
see 3.5-2 =1.5
now 1.5/2*100
75%
answer 75%

Answer 2

Answer:

$3.2 - 2.0 = 1.5$

Now

$\frac{1.5}{2} \times 100 = 75\%$

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