Question

5. A uniform disc rotating on a horizontal plane about a fixed vertical axis through its centre, experiences two forces as shown in figure. Given I
about axis of rotation 1 kg m; radius of disc, R = 10 cm. Then the angular acceleration is (rad s?) of magnitude​

Answer 1

Explanation:

Moment of inertia    I=2mr2=210×0.22=0.2 kgm2

Angular acceleration   α=Iτ=0.210=50 rad/s2

Initial angular velocity   wi=0

Using   wf=wi+αt

Or     wf=0+50×6=300 rad/s