5 ampere is passed through a solution of znso4 for 40 min find the amount of zinc deposited at the cathode
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Answered by
1
Answer:
4.065g of zn.
Explanation:
=65.39×120002×96500=4.065g of zinc.
Answered by
1
Answer:
A 5A current in passed through a solution of zinc sulphate for 40min. These amount of zinc deposited at the cathode is. =65.39×120002×96500=4.065g of zinc
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