5. Bob and Joe have few marbles. If Bob gives 1/4th of
his marbles to Joe, Bob will have the same number
of marbles as Joe has. Instead, If Joe gives 1/4th of
his marbles to Bob, Bob will have three times the
number of marbles Joe has. How many marbles did
Bob originally have?
Answers
Answered by
0
Answer:
Let Bob & Joe have x & y marbles, respectively.
By condition 1,
3x/4 = y + x/4 so y = x/2.
By condition 2,
9y/4 = x + y/4 so again y = x/2.
However, we can draw 2 conclusions now :
Bob has twice as much marbles as Joe.
From 2nd equation, it's clear that y/4 = x/8 is a natural number. So, number of marbles Bob has is a multiple of 8.
The given data in the question is insufficient for reaching the exact answer.
Answered by
0
5. Bob and Joe have few marbles. If Bob gives 1/4th of
his marbles to Joe, Bob will have the same number
of marbles as Joe has. Instead, If Joe gives 1/4th of
his marbles to Bob, Bob will have three times the
number of marbles Joe has. How many marbles did
Bob originally have?
Attachments:
Similar questions