Question

5. Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.
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Answer 1

Answer:

• 240 cm² is the required area of Trapezium.

Step-by-step explanation:

According to the Question

It is given that,

• Length of Parallel side 15 & 25 cm
• Distance between them ,h = 12cm

we have to calculate the area of trapezium .

As we know that ,

Area of Trapezium = ½ × (sum of parallel side) × distance between them

On substituting the value we get

↠ Area of Trapezium = ½ × (15+25) × 12

↠ Area of Trapezium = ½ × (40) × 12

↠ Area of Trapezium = 20 × 12

↠ Area of Trapezium = 240 cm²

• Hence, the area of trapezium is 240cm².

Additional Information !!

$\begin{gathered}\boxed{\begin {array}{cc}\\ \quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

Answer 2

Answer:

Given :-

• A length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

To Find :-

• What is the area of a trapezium.

Formula Used :-

$\clubsuit$ Area Of Trapezium Formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height}}\: \: \: \bigstar$

Solution :-

Given :

• Length of Parallel Sides = 15 cm and 25 cm
• Height = 12 cm

According to the question by using the formula we get,

$\footnotesize \implies \sf\boxed{\bold{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height}}$

$\small \implies \bf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (a + b) \times h$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (15 + 25) \times 12$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (40) \times 12$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times 480$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1 \times 480}{2}$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{\cancel{480}}{\cancel{2}}$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{240}{1}$

$\implies \sf\bold{\underline{Area_{(Trapezium)} =\: 240\: cm^2}}$

$\therefore$ The area of a trapezium is 240 cm² .