Question

5. If alph and Beta roots of the equation x2 - 3x + 6 = 0, find the value of alpha2+ beta 2
da cylinder
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Answer 1

if alpha + beeta = 3

so 2( alpha + beeta)

= 2( 3)

= 6

so anwer is 6

Answer 2

D = b² - 4 × a × c

D = (-3)² - 4 × 1 × 6

D = 9 - 24

D = -15

And the equations whose D < 0 has no real roots.

So recheck the question.