Question

5. If P(2,5), Q(-3,-7) then find length of PQ? ​

Answer 1

Answer:

PQ=13

Step-by-step explanation:

The distance (d) between the points (x_2,x_1) and (y_1,y_2) is

$d = \sqrt{ {(x _{2} - x _{1})}^{2} + {(y _{2} - y _{1})}^{2}}$

$d = \sqrt{ {(2 -( - 3))}^{2} + {( 5 - (- 7))}^{2}} \\ d = \sqrt{25 + 144} \\ d = \sqrt{169} = 13$

The distance between these points is 13 units i.e PQ = 13