5.) In Fig. 11.29, PQR is an isosceles triangle with PR - QR. , = 5 P 80° R b Fig. 11.29 If ZP-80°, find (a) ZPQR and Z PRQ, and (b) the values of Za and Zb.
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/_ PQR is 80° because base angles of isosceles triangle are equal. (PR and QR are equal sides so /_ RPQ = /_ RQP)
/_ PRQ is 20° because of the angle sum property of triangles ; 180°= /_ PQR + /_ PRQ + /_ RPQ which is 180° = 80° + /_ PRQ + 80° so /_ PRQ is 20°
/_ a is 100° by linear pair (180° = 80° + a)
/_ b is 160° by linear pair (180° = 20° + b)
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