Question

5. In triangle ABC, AB = AC. If angle A = 50°, then find angle B and angle C.
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Answer 1

Answer:

Given,

AB=AC

A is the common angle

Then,

50+x+x=180

2x =180-50

x=130/2

x=65'

Answer 2

Answer:

Since,  Angle A + Angle B + Angle C = 180 {Angle sum property of a triangle}

Angle B + Angle C = 180 degrees - Angle A

Angle B + Angle C = 130 degrees

Since,  AB=AC (Given)

Therefore Angle B = Angle C {Angle opposite to equal sides of a triangle are equal}

Now, Let Angle C = Angle B (From Above)

Therefore,

=> Angle B + Angle B = 130 degrees

=> 2 * Angle B = 130 degrees

Angle B = 130/2 degrees

= 65 degrees

Therefore Angle B = Angle C = 65 degrees

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