Question

5 litre of N2 under a pressure of 2 atm, 2 litre of O2 at 5.5 atm and 3 litres of CO2 at 5 atm are mixed the resultant volume of the mixture is 15 litres calculate the partial pressure of each constituent​

Answer 1

Answer:

Explanation: artial pressure of N2 =Vol of N2 ×pressure of N2Total volume                                  =5×215                                   =0.66 atmPartial

pressure of N2 =Vol of N2 ×pressure of N2Total volume                                  =5×215                                   =0.66 atm[As P1V1 = P2V2, P1= P2V2/V1 , Boyle's Law]

Partial pressure of O2 =Vol of O2 ×pressure of O2Total volume                                  =2×5.515                                   =0.73 atmPartial pressure of O2 =Vol of O2 ×pressure of O2Total volume                                  =2×5.515                                   =0.73 atm

Partial pressure of CO2 =Vol of CO2 ×pressure of CO2Total volume                                  =3×515                                   =1 atmPartial pressure of CO2 =Vol of CO2 ×pressure of CO2Total volume                                  =3×515                                   =1 atm

Thus total partial pressure = 0.33+0.73+1 atm

                                         =2.06 atm

Answer 2

Answer:

Pf= 2.4

P.Po2= 0.733

P.PCO2=1

P.PN2= 0.66