√5-logx base 2=3-logx base 2
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0
hello..
not possible..because rrot 5 can never be equal to ..3
check your question..
not possible..because rrot 5 can never be equal to ..3
check your question..
vedantshirore:
It is whole root on left side
Answered by
2
5 - logx = 3^2 -( logx)^2 - 6logx
0 = 4 +( logx)^2 - 5logx
Let logx base 2 = t
t^2 -5t +4 = 0
t^2 -4t - t +4 = 0
t ( t -4) - (t - 4) = 0
(t - 1) (t - 4) =0
t = 1,4
logx =1
x = 2^1= 2
Again
logx = 2^4=16
0 = 4 +( logx)^2 - 5logx
Let logx base 2 = t
t^2 -5t +4 = 0
t^2 -4t - t +4 = 0
t ( t -4) - (t - 4) = 0
(t - 1) (t - 4) =0
t = 1,4
logx =1
x = 2^1= 2
Again
logx = 2^4=16
Thanks
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