Question

5.] One kg of air at a temperature of 20°C is heated to a temperature of 60°C. Find the heat supplied to
air when heated at constant pressure. The specific heat for air at constant pressure = 1 kJ/kg K.

mai nhi roo rhi
new I'd ... xD​

Answer 1

Explanation:

How does Valmiki describe the discrimination that the child had to face in the school in‘joothan'?

Answer 2

Answer:

$\huge\mathfrak\blue{AnsWer}$

Actually Welcome to the Concept of the Thermodynamics.

Here, we simply aaplya the formula for the heat energy gained by a gas due to change in the temperature.

Q = mc∆T

here, Q = heat energy, m = mass in kg, c = specific heat capacity and ∆T = change in temperature in K.

hence, 20° C = 293 K and 60° C = 333 K

so, we get as,

Q = (1 kg) (1 KJ / Kg K)(333 K - 293 K)

Q= (1)(1000 J/ Kg K)(40)

Q = (40,000 ) Joules

hence, the heat gained is => Q = 40 KJ

• yeah ! that's like mah mannat ❤️
• exams over hone ke baad full masti karenge..xD