Question

5. The parking charges of a car in Hyderabad Railway station for first two hours is
50 and 10 for each subsequent hour. Write down an equation and draw the graph.
Find the following charges from the graph
(i) For three hours (ii) For six hours
(iii) How many hours did Rekha park her car if she paid 80 as parking charges?​

Answer 1

Answer:

Let the number of hours parked = x

Parking charges = y = 50 + 10(x - 2)

[Because the charge is ₹50 for first two hours...]

So, the equation becomes:

y = 50 + 10x - 20

y = 10[5 - 2 + x]

y = 30 + 10x

(i) x = 3

y = 30 + 10(3) = ₹60

ii) x = 6

y = 30 + 10(6) = ₹90

iii) y = ₹80

80 = 30 + 10x

x = (80 - 30) /10

x = 50/10 = 5

x = 5 hours.

See graph in attachment. (WARNING: graph isn't neat.)

Answer 2

Answer:

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