Question

5/x+6y=13,3/x+20y=35solve and find the value of x,y

Answer 1

Answer:

$\frac{5}{x \: + 6y} = 13 \\ \\ \frac{3}{x \: + 20y} = 35 \\ \\ \: y \: crossultiplication \: \\ \\ 13x + 78y = 5 \\ \\ 35x + 700y = 3$

$by \: multipling \: 35 \: in \: 1st \: eq.and \: 13 \: in \: second \: eq.$

$455x + 2730y = 175 \\ \\ 455x + 9100y = 39$

$by \: elimination \: method \: \\ \\ 6370y = 136 \\ \\ y \: = \frac{136}{6370}$