Math, asked by nithyard09266, 1 month ago

5/x + 6y =3 and -5/x + 3y =6
chapter:- Pair of Linear Equations in two Variables

Answers

Answered by muhammadayaz1083
0

Answer:

Step-by-step explanation:

add both eq.

9y = 9

y = 1

put y in eq 1

5/x + 6(1) = 3

5/x = 3 - 6

5/x = -3

5 * -3 = x

x = -15

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

5/x + 6y =3

-5/x + 3y =6

To find :-

Solve the equations ?

Solution :-

Given equations are :

5/x + 6y =3 ----------(1)

-5/x + 3y =6---------(2)

Put 1/x = a then

5a + 6y = 3 ---------(3)

-5a + 3y = 6 --------(4)

On adding (3)&(4) then

5a + 6y = 3

-5a + 3y = 6

(+)

___________

0 + 9y = 9

___________

=> 9y = 9

=> y = 9/9

=> y = 1

On Substituting the value of y in (3)

=> 5a +6(1) = 3

=> 5a +6 = 3

=> 5a = 3-6

=> 5a = -3

=> a = -3/5

now

a = -3/5

=> 1/x =-3/5

=> x = -5/3

Therefore, x = -5/3 and y = 1

Solution :-

Solution for the given equations is ( -5/3,1)

Check:-

If x = -5/3 and y = 1 then

LHS of equation (1) = 5/x+6y

=> [5/(-5/3) ]+ 6(1)

=> (-15/5 )+ 6

=> -3+6

=> 3

=> RHS

LHS = RHS

LHS of equation (2)

=>-5x+3y

=>[ -5/(-5/3)] +3(1)

=> (15/5) + 3

=> 3+3

=> 6

=> RHS

LHS = RHS

Verified the given relations in the given problem.

Used Method:-

  • Reducible to linear equations
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