5 x^7 / root of 5 x^ 3
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Answer:
what you need to do is square each side of the equation to get rid of the roots. you will need to do this twice
first time
(sqrt (5x+7) -sqrt (3x+1)) ^2 = sqrt (x+3)^2
multiply out the brackets to get
5x+7 -2sqrt (3x+1)(5x+7) + 3x+1 =x+3
put the sqrt expression on one side of the = sign to get
7x+5 = 2 sqrt (3x+1)(5x+7)
now square each side again
(7x+5) (7x+5) = 2^2 (sqrt (3x+1)^2) (sqrt (5x+7)^2)
49x^2 +70x +25 = 4 (3x+1) (5x+7)
11x^2 -38x +3 +0
use the formula to solve this
i am in a bit of a rush so cannot check my arithmatic, but the method should be correct
Answered by
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Answer:
5x^7/√5x^3. =5x^7/5x^3*1/2. =5x^7-3/2.
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