5 year hence ratio of ages of a and b will be 7 : 5 and difference between their ages will be 4 years. what are present ages (in years) of a and b respectively?
Answers
Solution :-
Let the present ages of a and b be x years and y years respectively.
Case I : 5 year hence ratio of ages of a and b will be 7 : 5
=> (x - 5)/(y - 5) = 7/5
=> 5(x - 5) = 7(y - 5)
=> 5x - 25 = 7y - 35
=> 5x - 7y = - 10 _______(i)
Case II : Difference between their ages will be 4 years.
=> x - y = 4
=> x = 4 + y _______(ii)
Put the value of x in equation (i)
=> 5(4 + y) - 7y = - 10
=> 20 + 5y - 7y = - 10
=> 2y = 30
=> y = 15
Now, put the value of y in equation (ii) we get,
=> x = 4 + 15 = 19
Hence,
The present ages of a and b are 19 years and 15 years respectively
☞ 5 year hence ratio of ages of a and b will be 7 : 5.
Let present age of a be 'M' and present age of b be 'N'.
• 5 years hence
Age of a = M - 5
And age of b = N - 5
• Ratio of their ages is 7 : 5
=> =
Cross-multiply them
=> 5(M - 5) = 7(N - 5)
=> 5M - 25 = 7N - 35
=> 5M - 7N = - 35 + 25
=> 5M - 7N = - 10 _________(eq 1)
_____________________________
☞ Difference between their (a and b) ages is 4 years.
=> M - N = 4
=> M = 4 + N __________(eq 2)
• Put value of M in (eq 1)
=> 5(4 + N) - 7N = - 10
=> 20 + 5N - 7N = - 10
=> - 2N = - 10 - 20
=> - 2N = - 30
=> 2N = 30
=> N = 15
• Put value of N in (eq 2)
=> M = 4 + (15)
=> M = 19
______________________________
Present age of a = M = 19 years
and
Present age of b = N = 15 years
______________[ANSWER]