Question

5 years ago a man was seven times as old as his son while 5 years hence the man will be 4 times as old as his son. Find their present age

Answer 1

Answer:

Present age of man is 75 years and present age of son is 15 years.

Step-by-step explanation:

Let the age of the man be x years and the age of his son be y years.

5 years ago:

Age of man = x-5

Age of son = y-5

5 years later:

Age of man = x+5

Age of son = y+5

Equation 1:

x-5 = 7(y-5)

x-5 = 7y - 35

x - 7y = -35 + 5

x - 7y = -30

Equation 2:

x+5 = 4(y+5)

x+5 = 4y + 20

x - 4y = 20-5

x - 4y = 15

Subtract eq 1 from eq 2:

x - 4y - (x - 7y) = 15 - (-30)

x - 4y - x + 7y = 15 + 30

3y = 45

y = 15 years

x - 4y = 15

x = 15 + 4(15) = 15 + 60 = 75 years

The man's current age is 75 years and the son's current age is 15 years.

If there's any mistake, please tell. I hope this helps!

Answer 2

Answer:

Step-by-step explanation: