Math, asked by ana205, 1 year ago

5 years ago, the sum of the ages of Kavita and Reema was 70 years and their ages were in ratio 3:4. Find the ratio of their present ages.

Answers

Answered by ashi2203
35
FIVE YEARS BEFORE :
let kavita`s age = 3x
let reema`s age = 4x
3x + 4x = 70
7x = 70
x = 70/7
x = 10
kavita`s age = 3*10=30years
Reema`s age = 4*10 = 40 years

PRESENT AGE:
kavita`s age = 30+5 = 35years
reema`s age = 40+5 = 45 years

ana205: thanks!
ashi2203: ur welcome
Answered by Manogna12
26

\huge\fcolorbox{black}{pink}{Question}

5 years ago, the sum of the ages of Kavita and Reema was 70 years and their ages were in ratio 3:4. Find the ratio of their present ages.

\huge\fcolorbox{black}{pink}{Answer}

\underline{\underline\orange{To Find:}}

The ratio of their present ages.

\underline{\underline\orange{Given:}}

5 years ago :

\orange\rightarrow Sum of ages of Kavita and Reema = 70

\orange\rightarrow Ratio = 3:4

\underline{\underline\orange{Solution:}}

Let, The age of Kavitha be 3x

The age of Reema be 4x

\orange\Rightarrow 3x + 4x = 70

\orange\Rightarrow 7x = 70

\orange\Rightarrow x = \frac{70}{7}

\orange\Rightarrow x = 10

\green{Five\: years\:ago}:

The age of Kavitha = 3x = 3×10 = 30

The age of Reema = 4x = 4×10 = 40

\green{Present}:

Age of Kavitha = 30+5 = 35

Age of Reema = 40+5 = 45

\thereforeThe ratio of their present ages = 35:45 = 7:9

\sf\blue{hope\:it\:helps}

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