5 years ago, the sum of the ages of Kavita and Reema was 70 years and their ages were in ratio 3:4. Find the ratio of their present ages.
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Answered by
35
FIVE YEARS BEFORE :
let kavita`s age = 3x
let reema`s age = 4x
3x + 4x = 70
7x = 70
x = 70/7
x = 10
kavita`s age = 3*10=30years
Reema`s age = 4*10 = 40 years
PRESENT AGE:
kavita`s age = 30+5 = 35years
reema`s age = 40+5 = 45 years
let kavita`s age = 3x
let reema`s age = 4x
3x + 4x = 70
7x = 70
x = 70/7
x = 10
kavita`s age = 3*10=30years
Reema`s age = 4*10 = 40 years
PRESENT AGE:
kavita`s age = 30+5 = 35years
reema`s age = 40+5 = 45 years
ana205:
thanks!
Answered by
26
5 years ago, the sum of the ages of Kavita and Reema was 70 years and their ages were in ratio 3:4. Find the ratio of their present ages.
The ratio of their present ages.
5 years ago :
Sum of ages of Kavita and Reema = 70
Ratio = 3:4
Let, The age of Kavitha be 3x
The age of Reema be 4x
3x + 4x = 70
7x = 70
x =
x = 10
The age of Kavitha = 3x = 3×10 = 30
The age of Reema = 4x = 4×10 = 40
Age of Kavitha = 30+5 = 35
Age of Reema = 40+5 = 45
The ratio of their present ages = 35:45 = 7:9
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