Math, asked by araveenpipavath, 1 month ago

50
(a)
(V) In the figure, XY and X'y' are two parallel tangents to
circle with centre 0 and another tangent AB with point
of contact C intersecting XY at A and X'Y' at B then angle BOA

(a)80°
(b)100°
(c)90°
(d)60°

Answers

Answered by abhynikam12
0

Step-by-step explanation:

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Answered by OoExtrovertoO
1

Answer:

Qᴜᴇꜱᴛɪᴏɴ:

ɪɴ ꜰɪɢ., xʏ ᴀɴᴅ x'ʏ' ᴀʀᴇ ᴛᴡᴏ ᴘᴀʀᴀʟʟᴇʟ ᴛᴀɴɢᴇɴᴛꜱ ᴛᴏ ᴀ ᴄɪʀᴄʟᴇ ᴡɪᴛʜ ᴄᴇɴᴛʀᴇ ᴏ ᴀɴᴅ ᴀɴᴏᴛʜᴇʀ ᴛᴀɴɢᴇɴᴛ ᴀʙ ᴛᴏᴜᴄʜɪɴɢ ᴀᴛ ᴄ, ɪɴᴛᴇʀꜱᴇᴄᴛɪɴɢ xʏ ᴀᴛ ᴀ ᴀɴᴅ x'ʏ' ᴀᴛ ʙ. ᴘʀᴏᴠᴇ ᴛʜᴀᴛ ᴢᴀᴏʙ = 90°.

ꜱᴏʟᴜᴛɪᴏɴ :

ʟᴇᴛ ᴜꜱ ᴊᴏɪɴ ᴘᴏɪɴᴛ ᴏ ᴛᴏ ᴄ.

ɪɴ ᴀᴏᴘᴀ ᴀɴᴅ ᴀᴏᴄᴀ,

ᴏᴘ = ᴏᴄ (ʀᴀᴅɪɪ ᴏꜰ ᴛʜᴇ ꜱᴀᴍᴇ ᴄɪʀᴄʟᴇ)

ᴀᴘ = ᴀᴄ (ᴛᴀɴɢᴇɴᴛꜱ ꜰʀᴏᴍ ᴘᴏɪɴᴛ ᴀ)

ᴀᴏ = ᴀᴏ (ᴄᴏᴍᴍᴏɴ ꜱɪᴅᴇ)

ᴀᴏᴘᴀ = ᴀᴏᴄᴀ (ꜱꜱꜱ ᴄᴏɴɢʀᴜᴇɴᴄᴇ ᴄʀɪᴛᴇʀɪᴏɴ)

ᴛʜᴇʀᴇꜰᴏʀᴇ, ᴘ ᴄ, ᴀ + ᴀ, ᴏ - ᴏ

ᴢᴘᴏᴀ = ᴢᴄᴏᴀ ... (1)

ꜱɪᴍɪʟᴀʀʟʏ, ᴀᴏQʙ = ᴀᴏᴄʙ

ᴢQᴏʙ = 2ᴄᴏʙ . (ɪɪ) ...

ꜱɪɴᴄᴇ ᴘᴏQ ɪꜱ ᴀ ᴅɪᴀᴍᴇᴛᴇʀ ᴏꜰ ᴛʜᴇ ᴄɪʀᴄʟᴇ, ɪᴛ ɪꜱ ᴀ ꜱᴛʀᴀɪɢʜᴛ ʟɪɴᴇ.

ᴛʜᴇʀᴇꜰᴏʀᴇ, ᴘᴏᴀ + 2ᴄᴏᴀ + ᴄᴏʙ + ᴢQᴏʙ = 180°

ꜰʀᴏᴍ ᴇQᴜᴀᴛɪᴏɴꜱ (ɪ) ᴀɴᴅ (ɪɪ), ɪᴛ ᴄᴀɴ ʙᴇ ᴏʙꜱᴇʀᴠᴇᴅ ᴛʜᴀᴛ

2∠ᴄᴏᴀ+2∠ᴄᴏʙ=180∘

∠ᴄᴏᴀ+∠ᴄᴏʙ=90∘

∠ᴀᴏʙ=90∘

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