Question

50 cal of heat is required to raise the temperature of 1 mole of an ideal gas

Answer 1

Question - 50 Cal of heat is required to raise the temperature of 1 mole of an ideal gas from 20°C to 25°C, while the pressure of the gas is kept constant. The amount of heat required to raise the temperature of the same gas through same temperature range at constant volume is?

Answer - 40 cal

Given,

• Cp = 50 cal  

According to the equation ,

• Cp=Cv+nR (T2-T​1)

Thus,

•    50=Cv + 1 * 1.98 * 5 {value of R in cal / (Kmol) is 1.98)}
• ⇒ Cv = 50 - 1 * 1.98 * 5 = 50 - 9.9 cal = 40.1 cal ≈ 40 cal

Answer 2

Hope it helps

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