Chemistry, asked by AlokPrabhakar5116, 10 months ago

50 mL of 0.5 M oxalic acid is needed to neutralize 25 ml of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is
(A) 40 g (B) 10 g
(C) 20 g (D) 80 g

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